Circumferential stress

## A cylinder is 300 mm mean diameter with a wall 2 mm thick. Calculate the maximum pressure difference allowed between the inside and outside if the stress in the wall must not exceed 150 MPa.

 

Solution:

This solution must be based on the circumferential stress since this is the largest.

Given,

           Diameter, D = 300 mm = 0.3 m

           Thickness, t = 2 mm = 0.002 m

           Maximum stress, σ = σ_c = 150 MPa

           Pressure difference, P =?

We know that,

Circumferential stress,

                                   σ_c = P.D/2t

                              => P = 2t σ_c/D

                              => P = (2 x 0.002 x 150) /0.3

                              => P = 2 MPa

So, the maximum pressure difference = 2 MPa