Elongation in a solid rod

## A steel rod of 1 cm² in cross-sectional area and 100 cm long is subjected to an axial pull of 2000 kgf. Find the elongation of the rod. Considering E= 200 GPa. 

Solution:

Given,

          Cross-sectional area, A = 1 cm²

          Length of rod, L = 100 cm

          Applied force, P = 2000 Kgf  (:: 1 Kgf = 9.81 N)

          Modulus of Elasticity, E = 200 GPa = 2x10⁶ Kgf/cm² (:: 1 Pa = 10^-5 Kgf/cm²)

          Elongation, 𝛿 =?

We know that, 

                      Elongation,

                                         𝛿 = P.L/A.E

                                            = (2000 x 100)/(2x10⁶ x 1)

                                            = 0.1 cm

 So, the elongation of the rod = 0.1 cm