## A single cylinder, two stroke petrol engine develops 4 KW
indicated power. Find the average speed of the piston, if the mean effective
pressure is 6.5 bar and piston diameter is 100 mm.
Solution:
Given,
Indicated power I.P = 4 KW
Mean effective pressure Pm = 6.5 bar
Piston diameter DP = 100 mm = 0.1 m
Let,
L = Length of stroke in meters
N = Speed of the engine in r.p.m
:: Number of working strokes per minute,
n= N (Engine works on two stroke cycle)
We know that area of piston,
A = π/4 x (0.1)2 = 7.855 x 10-3 m2
So, Indicated power (I.P),
=> I.P = (100 x Pm x L x A x n)/60
=> 4 = (100 x 6.5 x L x 7.855x10-3 x
N)/60
=> 4 = 0.0851 LN
=> LN = 47
So, Average speed of the piston,
= 2 x LN
= 2 x 47
= 94 m/sec
:: Average speed of the piston = 94 m/sec
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